∠ XAZ = ……

          radius XA || radius YB           ————(……………)

ii) If 5sin – 12cos = 0, find the value of sec.

Solution:

            5sin – 12cos = 0

          5sin = 12cos

            =

           =

We have,

            1 + tan2 = sec2

          1 +  = sec2

          sec2 =

          sec =

iii) The circumference of circular forces of a frustrum are 132cm and 88cm and its height is 24cm. To find the curved surface area of the frustum complete the following activity.  

Circumference1 = 2r1 = 132                                                 

                        r1 =  =

Circumference2 = 2r2 = 88                                       

                        r2 =  =

   Slant height of frustrum = l =

                                                =

                                                =

  Curved surface area of the frustrum =  l

                                                            =   

                                                            =  sq.cm

B) Solve the following sub-questions. (Any 4)                      ——————–(8)

i) In ∆ABC, DE || BC, If DB = 5.4cm, AD = 1.8cm, EC = 7.2 cm then find AE.
ii) In ∆PQR, ∠ Q = 900, ∠ P = 300, then find PQ and QR.

iii) In a circle with centre O, length of chord AB is equal to the radius of the circle. Find the measure of each of the following

  1. ∠ AOB            
  2. Arc AB                       

iv) Find k, if R(1, -1), S(-2, k) and slope of line RS is -2.

v) Person is standing at a distance of 50m from a building looking at its top. The angle of elevation is 600. Find the height of building.

Q.3 A) Complete the following activities. (Any 1)                ——————–(3)

i) In the figure, X is any point in the interior of triangle. Point X is joined to vertices of triangle. Seg PQ || seg DE, seg QR || seg EF. Fill in the blanks to prove that,

seg PR || seg DF.

Proof: In ∆XDE,

PQ || DE          ——————-                      

           =         ———– (I)    (Basic proportionality theorem)

In ∆XEF,

QR || EF          ——————-

           =         ———– (II)   ()

           =         ———–(From I and II)

         seg PR || seg DE          ——-(converse of basic proportionality theorem)

ii) If point P(-4, 6) divides the line segment AB with A(-6, -10) and B(a, b) in the ratio 2:1, find the co-ordinate of B.

Solution:

Suppose, P(-4, 6) = (x, y)

By section formula,

                        x =  

                      -4 =

                      -4 =

                      -12 = 2r – 6

                        2r =

                          r =

And,

                        y =  

                      6 =

                      6 =

                      18 = 2s + 10

                        2s =

                          s =

Co-ordinate of point B are ( , ).

Q. 3 B) Solve the following sub-questions. (Any 2)              ——————–(6)

i) Find the length of the side and perimeter of an equilateral triangle whose height is  cm.

ii) Prove that: Opposite angles of a cyclic quadrilateral are supplementary.

iii) Draw a circle with radius 4.1cm, Construct tangents to the circle from a point at a distance 7.3cm from the centre.

iv) In radius of circle is 3.4cm and perimeter of sector P-ABC is 12.8cm. Find A(P-ABC).

Q.4 Solve the following sub-questions. (Any 2)                    ——————–(8)

i) From the information given in the figure, prove that PM = PN =  a

ii) ∆ABC  ∆PQR, in ∆ABC, AB = 5.4cm, BC = 4.2cm, AC = 6cm. AB: PQ = 3:2. Construct ∆ABC and ∆PQR.

iii) While landing at an airport, a pilot made an angle of depression of 200.  Average speed of the plane was 200 km/hr. The plane reached the ground after 54 seconds. Find the height at which the plane was when it started landing. ( sin 200 = 0.342).

Q.5 Solve the following sub-questions. (Any 1)                    ——————–(3)

i) The circles with centres P and Q touch each other at R. A line passing through R meets the circles at A and B respectively. Prove that,

a) seg AP || seg BQ                                        

b) ∆APR  ∆RQB

c) Find ∠RQB, if ∠PAR = 350.

ii) Prove that:  = sec2 + tan

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